MATH201 Final: MATH 201 UofA Final Exam Solution 1.LA

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31 Jan 2019
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Multiple choice problems: the equation is linear and already of the form y + p(x) y = q(x). So the integrating factor is: multiply both sides by = cos x, we have. Now y(0) = 0 gives 0 = c. so y = 7. = 1/3(cid:20) e x v = sin x + c cos x er (cid:16) 2 x ((cos x) y) = 5 +5x4(cid:17) = e sin x + c(cid:20) y = + c(cid:20) v = ex(cid:16) (cid:20) c = 0. v v = ex/3. 3 y 2 y + y 1 = ex/3. (cid:0) y 1(cid:1) (cid:20) y = (1) (2) (3) (4) (5) (6) (7) (8: to solve the bernoulli equation we need to divide both sides by y2 to get tan x and consequently y( /4) = 7/2. The answer is (e). which is linear, with integrating factor e x. So y = 3 (cid:0) e x v(cid:1) e(cid:16)c 1.

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