ENGG 3260 Study Guide - Specific Volume, Superheated Water, Joule
10 Apr 2013
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Problem 1: a rigid container contains saturated liquid water at 200 kpa. Internal energy: u = uf = 504. 50 kj/kg. Problem 2: a rigid container contains saturated vapor of water at 125 kpa. Therefore, it must be on the saturated liquid line as shown in the t-v diagram by a circular symbol ( ). Internal energy: u = ug = 2513. 0 kj/kg. Problem 3: a rigid container contains water vapor at 1 mpa and 300 c. Water is a vapor (unknown phase) inside the container. First identify the saturation temperature at given pressure (1 mpa) from. Now the intersection point of the 1 mpa pressure line and the 300 c temperature line will give you current state and you will see this is superheated water vapor. From superheated water table (table a6), internal energy, u=2793. 7 kj/kg. Problem 4: a rigid container contains unknown phase of water at 175 kpa.
