ECE318H1 Study Guide - Midterm Guide: Secondary Mirror, Primary Mirror, Eyepiece

• School: UTSG
• Department: Electrical and Computer Engineering
• Course: ECE318H1
• Professor: Li Qian

Document Summary

Tutorial-3-solutions: in this question, the primary mirror, secondary mirror and the eye piece will be denoted with subscripts 1, 2 and 3 respectively. The heights of the object to the primary mirror, secondary mirror and eyepiece will be yo, y1 and y2 respectively. Given f1 = 12 ft. ; d12 = 10 ft. is the distance between the primary and secondary mirrors; f3 = 4 in a). Position of the image with respect to secondary mirror is given by d = 12 10 = 2 ft. This point is 2 ft. behind the secondary mirror. The image of the secondary mirror is formed at the vertex of the primary mirror, so si2 = 10 ft. So the angular magni cation is si2 so2(cid:17) y1 f3. For this part of the question si2 so2(cid:17) f1 f3. = 180. f2g = f2 = 2. 5 ft. 12si2g = 5si2g 30 s2 i2g. 17si2g + 30 = 0 (si2g 15) (si2g 2) = 0.