ITEC 1000- Final Exam Guide - Comprehensive Notes for the exam ( 35 pages long!)

• School: York University
• Department: Information Technology
• Course: ITEC 1000
• Professor: Peter A Khaiter

Document Summary

537 / 2 = 268 remainder 1 and 0. 5. 268 / 2 = 134 remainder 0 x 2. 134 / 2 = 67 remainder 0 1. 0. 6. a 67678 = 1102 1112 1102 1112 = 11012 11112 01112 = df716. 6. b be8116 = 10112 11102 10002 00012 = 0012 0112 1112 0102 0002 0012 = 13. 7. a 120101. 012 this cannot be a valid number in base 2, since 2 is not a proper digit in base. 7. b 471. 568 this a proper number in base 8. 7. c bh. a716 this cannot be a valid hex number, since h is not a proper digit in base: e, a, the correct answer is c. 11. a 512510 = 10100000001012 therefore, it will take 13 bits. 11. b 2 bytes: from 0 to 213 -1 (or 0 to 8192-1 or 0 to 8191, the correct answer is d.