16.5.29 Question Help Find an equation for the plane tangent to the circular cylinder r(θ,z) = (6 sin (20)) i + (12 si naj j + z k at Po (3/3,9,1) corresponding to (0,2)-3,1 | . Then find a Cartesian equation for the surface and sketch the surface and tangent plane together The tangent plane at a point Poff(lu).g(u.v),h(u,v)) on a parameterized surface r(uv)-f(uv)i+ g(u.v)i+ h(u.v) k is the plane through Po normal to the vector ru (uo,vo) à rv (uo-vo) , the cross product of the tangent vectors at Po Choose the correct equation for the tangent plane below. OB 6V3x+6y = 0 6/3x+6y = 108 O C. 6x+6 3y 108 D. A Cartesian equation for the surface is â¡-36 (Type an expression using x, y, and z as the variables.)