MAT-3110 Midterm: MATH 3110 App State Spring2015 Test3 answer key

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15 Feb 2019
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Name: answer key: (15 points) getting things in order. Q = { 1, i, j, k} is the group of quaternions. The order of g is |g| = |d3| |q| = 6 8 = 48. Yes, x has order 3 in d3 and i has order 4 in q. [you may not assume that the kernel is a subgroup prove this as well. ] K = ker( ) = {g g | (g) = e} Therefore, k is a subgroup of g: suppose g g and x k. then (x) = e and so (gxg 1) = (g) (x) (g 1) = (g) e (g) 1 = e and so gxg 1 k. Thus, k is a normal subgroup of g: (25 points) quotients (a) given: h = {(1), (12)(34), (13)(24), (14)(23)} is a normal subgroup of s4. H is h = (1)h . ((1234)h) 1 = (1234) 1h = (1432)h [= (1234)h]

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