MATH 265 Midterm: MATH 265 Iowa State 265S12PT4

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15 Feb 2019
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Second practice midterm: let c be the curve de ned as follows, let c = (sin t, cos t) for 0 6 t 6 . Find cos(2 t) x(t) = (cid:12) t2 y(t) = (cid:12) (t 2)et + 3 t + 1. 2 6 t 6 3 z(t) = (cid:12) 10. Zc (2x + y cos(xy)) dx + (x cos(xy)) dy + 2 dz: let g be the surface corresponding to the cone z = px2 + y2 above the region in the plane satisfying. F = (cid:10)x3y, sin(z2) 2yz, z2 + 137x6(cid:11) F n d(sa): take the solid cylinder x2 + z2 6 4 with 0 6 y 6 3. Let g be the part of the boundary of the cylinder with z 6 0. I g(cid:28)xy z + x7, 137y x2 + zy, y xz(cid:29) t ds where g is oriented clockwise when viewed from above.

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