MATH 265 Final: MATH 265 Iowa State ch14 Finals

• School: Iowa State University
• Department: Mathematics
• Course: MATH 265
• Professor: All

Document Summary

Spring 2012 - administered: let c be the closed curve which consists of straight line segments between the points ( 3, 0), (3, 0) and (0, 3) where c is oriented counterclockwise. Ic(cid:18)y2 + cos(x3) x2y(cid:19) dx +(cid:18)2xy + 1 + e2y(cid:19) dy: let s be the sphere of radius 2 and f(x, y, z) = (cid:10)3xy2+ezy, 3x2y 3 cos(zx3), z3+17x25(cid:11). Spring 2012 - alternate: given the vector eld f(x, y) = (cos(x) + y)i + (ey + x)j and the curve c parameterized by x(t) = 2 cos(t) and y(t) = sin(t) with 0 6 t 6 , compute the following line integral: let c be the circle x2 + y2 = 4 oriented counter- clockwise. Ic (2x2 y3) dx + (x3 + ey) dy: evaluate rr s f n ds for the vector eld. F(x, y, z) = (x + y)i + (y 2x)j + (3x 2xy)k.