CHEM 1000 Midterm: CHEM 1000 Mizzou Exam 1
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E5 practice i: b, e, k, o, r, w, aa, ee (a) Ethyl-2-methylproprionate will not undergo claisen condensation to any appreciable degree, because the intermediate after the first two steps (deprotonation and addition-elimination), which are both unfavorable, the - keto ester that forms has no activated protons ( to both carbonyls). Claisen condensation, it is the deprotonation of this -keto ester (a highly. Oet favorable reaction) that is the driving force for the overall reaction. Since there are no activated protons, the overall equilibrium of the reaction lies to the left and very little product forms.
