PSIO 532 Study Guide - Final Guide: Inulin, Nephron, Peritubular Capillaries
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Thus, at low plasma concentrations of pah, all the pah is cleared from the plasma that goes through the nephrons (see below) in one pass. At higher plasma concentrations of pah, the tubules cannot secrete all the pah. Remember that the higher the plasma concentration of pah the closer its clearance (slope of the excretory rate) is to the gfr (curve #2). Curve #1 is the clearance of inulin, the gfr. Recall that total rpf is the flow to the nephrons plus the flow to perirenal structures. Apply to the diagram above: total rpf=600 ml/min and 600 mg of pah are dissolved in the plasma. Thus, apah = 1 mg/ml: of the total rpf, 60 ml/min (containing 60 mg of pah) bypasses the nephrons and. 540 ml/min (containing 540 mg of pah) perfuses the nephrons (effective rpf) If gfr = 100 ml/min, the filtrate contains 100 mg pah.
