MATH 151 Midterm: MATH 151 TAMU Y2013 2013a Exam 3b Solutions

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31 Jan 2019
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Exam iii version b solutions: e switch x and y and solve for y: x = 2xy + 5x = 8y 1, 2xy 8y = 5x 1, y = 5x 1. 8 2x: a using properties (e3 ln x)(ln(e2x)) (x3)(2x) = 2x4. of logarithms, eln(x3)(ln(e2x)), e using properties of logarithms, f (x) = ln(x4)+ln(ex) = 4 ln x+x, so f (x) = + 1: e let y = arcsin(cid:18) 1. Using the reference triangle below, tan y = 0 form limit so of the is indeterminate apply l"hospital"s rule: sin x lim x . 2 x2 = lim x cos x. 2 : c f is increasing when f is positive, and f is concave down when f is decreasing. Therefore, the correct interval (positive and decreasing) is (3, 5). 2: a f has a critical value when f (x) = cos x = (on the given interval).

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