MATH 151 Midterm: MATH 151 TAMU Y2015 2015a X2Combo
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Thu, 02/apr c?2015 art belmonte: (d) with f (x) = esin x, we have f ? (x) = esin x cos x and. Thus f ??: (b) with h (x) = x3 + g ( f (x)), we have. 9 4 = 2: (a) with x = t 2 4 and y = t/2, the point (12, 2) corresponds to t = 4. 16 : (b) when the diver hits the water his position (height, (e) with f (x) = tan x, we have f ? (x) = sec2 x and is zero. At this instant, the velocity is s? (2) or ( 16t + 8)|t=2 = 24 ft/s. f ?? (x) = 2 sec2 x tan x. 1+e 0. 25t 8: (c) as t , (a) with f (x) = x4, we have f ? (x) = 4x3. So (2. 01)4 = f (2. 01) l (2. 01) = 16. 32: (b) with f (x) = 1.
