MATH 151 Midterm: MATH 151 TAMU Y2009 2009c Exam 2a Solutions
Document Summary
We want to solve a(t) = 0, where a(t) is the acceleration. 2 this is true if t = t2, thus v(t) = cos t + Now, a(t) = 0 if sin t = , and: b: x3 + y3 = 6xy. = 18 + 18 dy dx dy dx. 3x2 + 3y2 dy dx and solve for dy dx. 27 + 27 dy dx: c: s(t) = t2 2t + 3. To nd the total distance traveled in the rst 3 seconds, we must rst nd where the velocity is positive and negative. v(t) = Hence the total distance traveled in the rst 3 seconds is |s(1) s(0)| + s(3) s(1) = | 1| + 4 = 5 feet. dy dt: a: the tangent line is horizontal when. = 3t2 6t = 3t(t 2). dx dt 6= 0. Now x = t2 2t + 4 and y = t3 3t2. dy.
