MATH 152 Midterm: MATH 152 TAMU 2013c Exam 3a Solutions
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= lim n (n + 1)! (2013)n+1 (2013)n n! n. 2013 r r t s r s s lim n (cid:12)(cid:12)(cid:12)(cid:12) an+1 an (cid:12)(cid:12)(cid:12)(cid:12) lim n . F (1) = f (1) = arctan 1 = R e x s t3(x) = 1 + ( x) + ( x)3. R r r p r x + e x s. 1 + x(cid:19) dx = c + x) ( 1)nxn+1 n + 1. X = 0, c = ln(1) = 0 r r x3 ln(1 + x) = Xn=0 ( 1)nxn+4 n + 1 t r s s r . S p( 6 0)2 + (0 ( 3))2 + ( 5 ( 5))2 = R x2 + (y + 3)2 + (z + 5)2 = 45 . 8n3 t |s sn| . R n s s n 3 500 1 . 4000 s t st t r s . T x z y = 0 s t r t .
