MATH 152 Midterm: MATH 152 TAMU Exam 3a Solutions 2018a
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Here are the multiple choice answers for version a. A: completing squares yields 2 (x 3)2 + (y + 4)2 = 44. 1 (8/5) cos , so e = 8: we have cos(2n)+3 n 2 n p-series (p = 1. So series diverges by comparison test. ln n ln(2n) = ln n: as n , via the alternating series estimation theorem, ln n +1 1. ln 2+ln n = 1 ln 2. 11: note an = ( 1)n(1+ 1 n ) So we have lim sup an = 1. The sequence {an} diverges lim inf an = 1 by the test for divergence: we have a3 = s3 s2 = 4. An = lim sn = lim n. 28 and: we have n=1 ( 1)n2n. 1 ( 2/5: let"s examine the statements one at a time, i. is true. For assume that an converges but lim an 6= 0. Then an diverges by the test for divergence, a contradiction.
