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Final

BIO SCI 93 Study Guide - Final Guide: Microtubule Organizing Center, Mendelian Inheritance, PseudopodiaExam


Department
Biological Sciences
Course Code
BIO SCI 93
Professor
All
Study Guide
Final

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Lecture A
Version A
Final Exam
ANNOTATED KEY
Bio 93 Fall 2011
Fill-out your name and ID# on your
scantron.
DO NOT begin the exam until instructed
to do so.
When finished, turn in scantron and
BOTH test packets.

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There are 35 multiple choice questions. There is one best answer for each question.
Question 1 is worth 0 points. Questions 2 - 35 are worth 2 points each for a total of
68 points.
1. You have version A. Please bubble in “A” for question 1. (0 points)
2. Kari, a Bio Sci 93 TA works with a protein called Tuba. When levels of Tuba are
lowered in somatic cells, the MTOC cannot function normally. Reducing Tuba levels in
interphase cells is likely to affect
a. Microtubule organization
b. Actin fiber formation
c. Kinesin binding to its cargo
d. Spindle poles
e. Myosin binding
Lecture 15, Ch 12. Level 3. The MTOC or microtubule organizing center controls how
microtubules are organized. If Tuba levels are lowered and the MTOC is disrupted, cells
would not be able to properly organize their microtubules. Actin polymerization and
kinesin binding will be unaffected. Spindle poles are not seen in interphase cells and
myosin will also be unaffected.
3. A group of cells is assayed for DNA content immediately following mitosis and is
found to have an average of 8 picograms of DNA per nucleus. How many picograms
would be found at the end of S and the end of G2?
a. 8; 8
b. 8; 16
c. 16; 8
d. 16; 16
e. 12; 16
Lecture 15, Ch 12. Level 3 Application. The cell cycle progression is represented as G1 -
>S ->G2 ->M ->G1. Immediately after mitosis the cell has a diploid DNA content of 8
pg. DNA synthesis takes place in S phase and mitosis does not commence till after G2.
Therefore the DNA content will double to 16 pg at the end of S phase and will not be
reduced to 8 pg till M phase.

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4. Addition of a drug that blocks formation of microtubules will most directly affect
which of the following functions of a white blood cell?
a. ability to detect bacteria that are nearby
b. extension of pseudopodia
c. transport of vesicles from the golgi to the plasma membrane
d. transport of sodium ions across the membrane through the sodium potassium
pump
e. control of water flow across the membrane through aquaporin channels
Lecture 4, 5, Chapters 6, 7, Comprehension. Vesicles are transported by motor proteins
along microtubules. The ability to detect nearby bacteria (a) does not depend on
microtubules. The extension of pseudopodia (b) is dependent on actin filaments and
myosin, not on microtubules. Microtubules are also not required for transport of Na+ ions
or control of water flow across the cell membrane.
5. A sexually reproducing plant has a diploid chromosome number of 10. What is the
minimum number of different gametes it can produce based on Mendel’s law of
independent assortment.
a. 10
b. 5
c. 100
d. 32
e. 16
Lecture 16, Chapter 13, integration. Since the diploid number is 10, the plant has 5 pairs
of homologous chromosomes. These can assort independently giving rise to 25 = 32
unique combinations of maternal and paternal chromosomes.
6. Mating of a female horse (mare) with a male donkey produces a mule. Horses have a
diploid chromosome number of 64 while donkeys have a diploid chromosome number of
62. Somatic cells from a male mule should contain:
a. 64 chromosomes
b. 62 chromosomes
c. 32 chromosomes
d. 31 chromosomes
e. 63 chromosomes
Lecture 16, Chapter 13, integration. The mule results from fusion of the haploid donkey
sperm (31 chromosomes) with the haploid horse egg (32 chromosomes) to produce a
zygote with 63 chromosomes).
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