calculate the pH of a .20M solution ofNH4Br.
We are given that Ka for NH4+ = 5.6 x 10-3.
From here we can obviously compute Kb.
1) Why do we use NH4+ <--> H+ + NH3- as opposed to using Br-+ H20 <---> BrH + OH- ?
2)Why do we set our ICE Table resulting equation equal to Ka asopposed to Kb?
- Find the PH of a .20 solution of KCN, we do CN- + H20<--> HCN + OH- . Why do we choose CN- instead of K and thenset this equal to Kb?
CHEM 2020 Chapter Notes - Chapter 8: Ammonia
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25 Sep 2017
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