MATH 2B Chapter Notes - Chapter 7.1: Product Rule, Algebraic Equation

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MATH 2B Full Course Notes
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MATH 2B Full Course Notes
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The best that can be hoped for with integration is to take a rule from differentiation and reverse it. Integration by parts is simply the product rule in reverse! d dx. [ f (x)g(x)] = f (x)g(x) + f (x)g (x) = f (x)g(x) = z f (x)g(x) dx + z f (x)g (x) dx. = z f (x)g (x) dx = f (x)g(x) z f (x)g(x) dx. Z u dv = uv z v du where u = f (x), du = f (x) dx, v = g(x), dv = g (x) dx. Moreover, you must know how to integrate the second factor before you start: the best it can achieve is to transform one integral into another. Hopefully this second integral is easier to compute. Examples: our rst example is very simple. We recognize the integrand xex as a product of two functions and choose the simpler u = x to be the function which we differentiate.

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