CHEM 20B Chapter Notes - Chapter 3: Lead, Potassium Dichromate, Fluoride

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10 Aug 2018
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The ions charges must (be multiplied to) make neutral compounds. We must have the same number of positive charges as negative charges, so that the total charge equals zero. Nitrate you will have memorized, since it has more than one element (more than one capital letter). A perfect match so just write down the compound. Notice, all of the negative single element ions in column #15, 16 and 17 now have -ide endings on their names. To make the +2 cancel with the -1, we must multiply the -1 by 2. Since we multiplied the cl by 2, there now appears a subscript 2 in the compound formula. **whenever we multiply that multiple becomes the subscript for that ion. It is fe and it is in the middle of the table. The roman numeral will tell us the amount of positive charge. The roman numeral iii in the name tells us it is +3 charged.

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