CH 301 Chapter Stoichiometry: Stoichiometry: Short Notes
Document Summary
1 mole = molar mass of the substance. 1 mole = 22. 4l of a gas at stp. 1 mol given: molar mass, 6. 02 x 1023 particles, 22. 4l x (y) mol sought (x) mol given x, molar mass, 6. 02 x 1023 particles, 22. 4l. Given the equation al(no3)3 + naoh al(oh)3 + nano3, find the mass of nano3 formed if 275g of naoh reacts. Balance equation = al(no3)3 + 3naoh al(oh)3 + 3nano3. Start with given amount (275g naoh) and solve for grams of nano3. 3 mol of nano3 because coefficient of nano3 in balanced equation is 3 . Molar mass of nano3 because question asks for mass . Molar mass of naoh because question gives info 275g of naoh .
