MATH 1P98 Lecture Notes - Lecture 8: Sample Space, Quartile

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We need a way to convert a normally dist. Real data may not have = 0, = 1, so it won"t be standard. Going from z to x: z + = Suppose heights are normally distributed with mean of 1. 58m and st. dev of 0. 35m. Then p(x < 1. 65) = p(z < 0. 2) = 0. 5793 from z-tables. The person is less than 1. 65m tall is 57. 93% We want to design a doorway so that 95% of people can walk through it without ducking. First, find z-value that corresponds to 0. 95: z = 1. 645 (avg. of 1. 64 and. Therefore, if doorway is 2. 1558m tall, then 95% of people can walk through it. Cost of insurance for 20 t/o student is norm dist. With a mean of a year and st. dev of . P( z < -1. 75) = 0. 0401 final answer. A student pays or less or 4. 01% P(x > 2200) = area to the right of 2200.

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