CHEM 120 Lecture Notes - Lecture 1: Ice Sheet, Heat Capacity

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CHEM 120 Full Course Notes
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CHEM 120 Full Course Notes
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To determine the molar heat of fusion of ice. You will know how much ice has melted by the increased volume and by the decrease of temperature: q=mc t, the specific heat or water is 4. 186 j/gm and 1. 00 cal/gm. Safety, materials, procedure: see molar heat of fusion of ice sheet. Processing: the water cooled from 56 c to 2 c. t = 56 - 2 = 54 c, qw=mwc t= (90)(1. 00)(54) = 4860cal or 20334. 24 j, qi=qw=4860 cal, vi=145-90 =55ml, 55g. 6: heat of fusion= heat to melt ice/ g or moles of ice = qi/g or moles = 4860cal/55g =88. 36 cal/g (55/1)(1mole of ice/18) = 3. 05mol. 4860/3. 05 = 1593. 44 cal/mol 20. 334/3. 05 = 6. 66 kj/mol. Questions: the values that represent the molar heat of fusion are 1593. 44 cal/mol and 6. 66 kj/mol. (88. 36-79. 8)/79. 8=10. 72% error. That the ice could have started melting before being placed in the styrofoam cup.

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