CHEM 222 Lecture Notes - Lecture 10: Free-Radical Halogenation, Saturated And Unsaturated Compounds, Bayerischer Rundfunk

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4c rings: any time can make sigma bonds, favorable, some molecules re-bind to metal surface (reversible) Mechanism of free radical halogenation/substitution: break br-br into 2 br. radicals, hydrogen abstraction: add br. radical + ch4 --> hbr + . ch3 radical. 3a) radical termination (minor) add two . ch3 radicals together or one . br and one . ch3. ch3 radical looks more like sp2 planar carbon. If do it with chlorine, still same major product but get closer ratio (45:55 between 1o and 2o rather than 3:97) In first step in making free radical, big climb (74 kj/mol) for bromine vs small for chlorine (8 kj/mol: cl- free radical more reactive & less selective for lower energy path, and. Br less reactive and more selective: reactivity: f2 > cl2 > br2 > i2. Just replace one ch bond, starting at most highly substituted carbon (tertiary: can"t be quaternary bc that means c is bonded to four other c, no ch bond.

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