MATLS 2B03 Lecture 2: Carnot cycle

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Carnot cycle
P
V
1
2
3
4
H
T
C
T
Isotherms
Adiabats
Path 1
2: isothermal expansion at TH
Heat flows from reservoir H to the system.
12 12 12
because heat received work done
the process reservoir H the system
is isothermal
d0 dUQ

 
from by
PV
 
12 12
dQPV

2
1
2
12 H
12 1
d
V
V
V
QPVRT
V

ln
1
(1)
Since , heat flows from reservoir H with temperature to the system.
2
VVH
T
In this step, work is done by the system. Numerically, it is equal to the area below the 12
line.
Path 2
3: adiabatic expansion
23 23 23 23
0becuase the work done
process is adiabatic the system
ddU Q PV PV
 

by
d
 
1
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Document Summary

Heat flows from reservoir h to the system. 1 2 heat received reservoir h from because the process is isothermal d. , heat flows from reservoir h with temperature. 2 dp v can be taken, there is no need to do this. In this step, work is done by the system. Heat flows from the system to reservoir c. 3 by work done the system because the process is isothermal. , which means that heat flows from the system to reservoir c having. It can be said that reservoir c received. Numerically, it is equal to the area below the. In this step, work is done on the system (system does negative work ). Numerically, it is equal to the area below the 1. When the system reaches point 1 again, the work w done by the machine during the whole cycle is equal to the area of the 12341 loop.

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