MATH114 Lecture Notes - Lecture 8: Squeeze Theorem, Classification Of Discontinuities

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Math 114 lecture 8 limits continuation. Theorem: if f(x) = g(x) in an open interval around x = a, then lim (cid:1858)(cid:4666)(cid:1876)(cid:4667)=lim (cid:1859)(cid:4666)(cid:1876)(cid:4667) Theorem: if f(x) g(x) near a (except possibly at a) and if the limits of f and g at a exist, (cid:1872)+(cid:886) (cid:886) (cid:1872)( (cid:1872)+(cid:886)+(cid:884)) If u(x) z(x) v(x) near a and lim (cid:1873)(cid:4666)(cid:1876)(cid:4667)= lim (cid:1874)(cid:4666)(cid:1876)(cid:4667)= (cid:1872) (cid:1857)(cid:1866) lim (cid:1878)(cid:4666)(cid:1876)(cid:4667)= http://www. intuitive-calculus. com/squeeze-theorem. html. Note: cannot plug x = 0 into 1/x, it would be undefined. Since -1 sin (cid:4666)(cid:2869)(cid:4667) 1 near x = 0 then. X2 (cid:1876)(cid:2870)sin (cid:4666)(cid:2869)(cid:4667) x2 near x = 0 and lim (cid:2868) (cid:1876)(cid:2870)= lim (cid:2868)(cid:1876)(cid:2870)=(cid:882) Definition: a function f is continuous at a if lim (cid:1858)(cid:4666)(cid:1876)(cid:4667)=(cid:1858)(cid:4666)(cid:1853)(cid:4667) In particular, f must be defined at a, and lim (cid:1858)(cid:4666)(cid:1876)(cid:4667) must exist. So if f is continuous at a, then taking lim (cid:1858)(cid:4666)(cid:1876)(cid:4667) is just taking f(a). Example: where are the following functions not continuous (cid:1858)(cid:4666)(cid:1876)(cid:4667)=(cid:1876)(cid:2870) (cid:885)(cid:1876)+(cid:884) (cid:1876) (cid:883)

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