BIO 3124 Lecture Notes - Lecture 2: Tropism, Hiv, Papillomaviridae

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turquoiseant153

25 Jan 2018

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October 18th lecture (slide 392 slide 422) What we should retain about replication of dna viruses: small genome vs large genome, small genome: replication occurs with a dna-dependent dna polymerase, which is the cellular polymerase. Large virus: replication occurs with a dna-dependent dna polymerase which is a viral polymerase. The strategies that rna viruses use: specifically, viruses that have a genome with a single strand of rna, therefore their genome is either positive or negative. Positive or negative strand: positive strand, sequence is that of mrna, can be translated into proteins. If the(cid:396)e(cid:859)s a ge(cid:374)o(cid:373)e (cid:449)ith a (cid:374)egati(cid:448)e st(cid:396)a(cid:374)d na, it (cid:272)a(cid:374)(cid:374)ot (cid:271)e u(cid:374)de(cid:396)stood (cid:271)(cid:455) the cell, cannot be deciphered by the cell, cannot be translated by the cell. If you want to retrieve the information from this rna, something needs to occur before translation. For viruses that have a positive rna genome.

Related Questions

You decide to identify the CFTR mutation by analyzing the genomic DNA of your patients compared to healthy individuals. You specifically are looking to see whether a specific 3' gene truncation has occurred in the patients. You will determine this using hybridization techniques with samples from healthy and CF patients. Which of the following will allow you to accomplish this?

	Using an RNA probe complementary to the region not removed by the truncation.
	Using an RNA probe complementary to the region removed by the truncation.
	Using an DNA probe complementary to the region not removed by the truncation.
	Using an DNA probe complementary to the region removed by the truncation.

To conduct the hybridization experiment, you are trying to decide between using a DNA or RNA probe. Which would be ideal to use and why?

	As both are composed of nucleic acids, using either would result in identical results.
	An RNA probe because RNA has uracil bases.
	An RNA probe because it could also be used in a translation experiment.
	A DNA probe because it is more stable than RNA.
	A DNA probe because RNA cannot bind to DNA.

Imagine Hershey/Chase had used an RNA virus (genome composed of RNA) instead of a DNA virus in their experiment. Would radioactivity still have been found in the pellet?

	No, because only DNA can be labeled with radioactivity.
	No, because the RNA genome would not enter the bacteria upon infection.
	No, because while DNA and RNA nucleotides are similar, they are not identical.
	Yes, because DNA and RNA nucleotides are similar.
	Yes, because genome in any form (DNA, RNA, protein) would be labeled similarly.

The human genome consists mostly of non-coding DNA. Which of the following are benefits of this?

	Random DNA mutations generally won't affect RNA and protein function.
	It is faster to duplicate the genome when these are present.
	The existence of introns can lead to multiple variations of proteins encoded by a single gene.
	It is unlikely transposons would exist in the genome if there was too much protein coding DNA.

You accidentally add a mutant dNTP (which has an H instead of an OH connected to the 3â carbon) to a reaction where DNA is being replicated. Which of the following is true of this mutant dNTP?

	It can be incorporated into DNA strand but cannot form a phosphodiester bond with an incoming wild type dNTP
	It can be incorporated into a DNA strand but cannot base pair with a complementary nucleotide
	It can be incorporated into a DNA strand and can form a phosphodiester bond with an incoming dNTP, but only if it is another mutant dNTP
	It cannot be incorporated into a DNA strand.

Andrew Murray's sister, Andrea, is adding to her brother's work on chromosomes. She is using cells that are unable to synthesize adenine (âade) and histidine (âhis). The plasmid she is currently working with consists of an origin of replication and the Ade gene.

Following her transformation of the plasmid into her yeast, what media will the cells be plated on to select for cells that have picked up the plasmid?

	Media containing histidine
	Media containing adenine
	Media lacking adenine
	Media lacking histidine

She starts by attempting to add the centromere DNA into a plasmid containing the origin of replication. Unfortunately, when adding the centromere sequence, the origin of replication is removed, thus leaving a plasmid with only a centromere and selection marker. Following plasmid transformation, what growth result will she see on her plates?

	No colonies
	Little colonies
	Big colonies

She fixes the mistakes from the previous experiment and now has a complete plasmid (selection marker, origin of replication, centromere). She then inserts telomere sequences into the plasmid. How will this impact her transformation?

	It will not impact her transformation
	Her transformation will no longer work because plasmids donât require telomeres
	She will now see much larger colonies
	She will now see fewer but larger colonies
	She will now see smaller colonies

In the Meselson/Stahl experiment, E. coli were first grown in media containing heavy nitrogen, 15N, and then transferred to light nitrogen, 14N, at the beginning of the experiment.

Imagine that their data showed that replication occurs in a conservative manner instead of semi-conservative. What fraction of the DNA helices will consist of mixed DNA after 4 rounds of replication in this case?

	None
	More than 75%
	25-50%
	51-75%
	Less than 25%

peachmarten804

Question 1

1 pts

Cystic fibrosis is caused by nonsense and missense mutations in the CFTR gene, which encodes for a chloride channel. You are studying cystic fibrosis patients to determine what mutation they possess in the CFTR gene. The difference between the mutant and wild type CFTR genes can be uncovered by examining the CFTR:

	DNA
	mRNA
	protein
	tRNA

Question 2

1 pts

	Using an RNA probe complementary to the region not removed by the truncation.
	Using an RNA probe complementary to the region removed by the truncation.
	Using an DNA probe complementary to the region not removed by the truncation.
	Using an DNA probe complementary to the region removed by the truncation.

Question 3

1 pts

You would like to ensure that this experiment (to determine whether patients have a specific CFTR gene truncation using hybridization) is properly controlled. Which of the following samples must you test?

	The genomic DNA of a healthy individual who does not have cystic fibrosis.
	The genome of a CFTR patient known to have the specific truncation you are trying to identify.
	The genome of a CFTR patient with a missense mutation but full length gene.
	The genome of a healthy individual married to a CFTR patient with the specific truncation you are trying to identify.
	The genome of a patient with muscular dystrophy, which can be due to a trucation in the dystrophin gene.

Question 4

1 pts

To conduct the hybridization experiment, you are trying to decide between using a DNA or RNA probe. Which would be ideal to use and why?

	As both are composed of nucleic acids, using either would result in identical results.
	An RNA probe because RNA has uracil bases.
	An RNA probe because it could also be used in a translation experiment.
	A DNA probe because it is more stable than RNA.
	A DNA probe because RNA cannot bind to DNA.

Question 5

1 pts

Which of the following will lower the Tm of a given DNA strand?

	Increasing the percentage of GC base pairs.
	Raising the pH of the solution from neutral to basic.
	Decreasing the buffer concentration from 50mM NaCl to 5mM NaCl.
	None of the above.

Question 6

1 pts

One step of the Hershey/Chase experiment involved blending the virus/cell mixture before centrifugation and probing the pellet for radioactivity. Why was the blending step necessary?

	To collect the bacteria at the bottom of the tube.
	To break open the bacteria to release the genome.
	To separate the bacteria from the bacteriophages.
	To be able to detect the radioactivity.

Question 7

1 pts

Imagine Hershey/Chase had used an RNA virus (genome composed of RNA) instead of a DNA virus in their experiment. Would radioactivity still have been found in the pellet?

	No, because only DNA can be labeled with radioactivity.
	No, because the RNA genome would not enter the bacteria upon infection.
	No, because while DNA and RNA nucleotides are similar, they are not identical.
	Yes, because DNA and RNA nucleotides are similar.
	Yes, because genome in any form (DNA, RNA, protein) would be labeled similarly.

Question 8

1 pts

Griffith and Avery's transformation experiments allowed us to identify that DNA is our genetic information. Which of the following scenarios would result in bacterial cells that are capable of killing mice upon injection?

	Heat killed non-virulent bacteria is added to a live virulent bacteria strain.
	Heat killed virulent bacteria is added to a heat killed non-virulent bacteria strain.
	A heat killed virulent bacteria that is treated with a nuclease, is then added to a non-virulent bacteria strain.
	Heat killed mouse cells are added to a non-virulent bacteria.

Question 9

1 pts

The human genome consists mostly of non-coding DNA. Which of the following are benefits of this?

	Random DNA mutations generally won't affect RNA and protein function.
	It is faster to duplicate the genome when these are present.
	The existence of introns can lead to multiple variations of proteins encoded by a single gene.
	It is unlikely transposons would exist in the genome if there was too much protein coding DNA.

Question 10

1 pts

Following her transformation of the plasmid into her yeast, what media will the cells be plated on to select for cells that have picked up the plasmid?

	Media containing histidine
	Media containing adenine
	Media lacking adenine
	Media lacking histidine

tealcockroach755

1. Unlike Ebola virus, SARS virus
a. has large spikes that look like a âcrownâ.
b. is enveloped.
c. is helical.
d. is in the family Togaviridae.
e. is a ssRNA virus.

2. Which virus or virus family is described in the followingpassage?
Electron micrographs of the hemagglutinin subunits (in the presenceof SDS) showed
rods approximately 40 Ã wide and 140 Ã long. The neuraminidasesubunits had a quite
different appearance. In the presence of SDS, these were seen asoblong structures about 85 Ã long and 50 Ã wide with a centrallyattached fibre 100 Ã long possessing what appeared to be a diffusetail or small knob about 40 Ã in diameter at its end.1
a. Togaviridae
b. Epstein-Barr virus
c. Smallpox virus
d. Orthomyxoviridae
e. Filoviridae
f. Rabies virus

3-Following is a passage from the New England Journal ofMedicine:
______________________ is an exclusively human herpesvirus that ...becomes latent in
cranial-nerve and dorsal-root ganglia, and frequently reactivatesdecades later to produce shingles and postherpetic neuralgia. Inimmunocompetent elderly persons or
immunocompromised patients, ____________________ may producedisease of the central nervous system.
This passage refers to which virus?
a. West Nile virus
b. Smallpox virus
c. Epstein-Barr virus
d. Ebola virus
e. Varicella-zoster virus

4. Pneumoviruses can cause colds and pneumonia in humans. They aresingle-stranded,
negative-sense, nonsegmented RNA viruses. These enveloped virusesare surrounded by an envelope that is characterized by fusionglycoproteins and host-derived proteins. With this knowledge, it islikely that pneumoviruses
a. enter host cells via endocytosis.
b. leave host cells by budding.
c. enter host cells via membrane fusion.
d. A and B
e. B and C

5. Recall that poliovirus is a positive-sense (+) ssRNA virus. The5â Ã ? 3â strand of RNA,
once uncoating has taken place, can serve as an mRNA and encode forviral proteins.
However, in order for the virus to create more +ssRNA to package indaughter viruses, it must
a. generate a dsRNA molecule that can encode for the synthesis ofmore +RNA.
b. integrate into the host cell DNA.
c. utilize an RNA-dependent DNA polymerase to make aheteroduplex.
d. undergo reassortment
e. All of the above

6. Some influenza hosts, such as humans and pigs, cansimultaneously contract human,
avian and swine influenza viruses at the same time. What can occurduring the maturation phase of virus replication in such ahost?
a. Reassortment
b. RNA of all three sources: human, swine and avian, can bepackaged into a single
virion.
c. Genetic shift
d. All of the above

7. The HIV virion contains enzymes/proteins that do all of thefollowing EXCEPT
a. An enzyme that creates âDNA using +RNA as template.
b. A protein that serves as a chemokine receptor.
c. A DNA-dependent DNA polymerase.
d. An enzyme that allows +/- viral DNA to be spliced into the hostcellâs DNA.
e. A protein that mediates membrane fusion.

8. After a long series of biochemical tests, Kyle and Matt werefinally able to identify their Gram-negative unknowns asPseudomonas aeruginosa and Shigella dysenteriae,
respectively. As they compare notes, they realize that theirunknowns are in the
___________ Pseudomonadaceae and Enterobacteriaceae, respectively.However, they also note that both of their unknowns are in the______________ ? proteobacteria.
a. genera, species
b. phyla, family
c. families, class
d. order, phyla
e. classes, order

9-Hydrogenobaculum acidophilum is a resident of YellowstoneâsNorris Geyser basin. This thermoacidophilic microbe grows instringy, white mats and is a member of the phylum Aquificae.Hydrogenobaculum acidophilum
a. could be further researched in Volume 2 of Bergeyâs Manual ofSystematic
Bacteriology.
b. is in the domain Archaea.
c. is a deeply branching bacterium.
d. is a proteobacterium.
e. All of the above

10-After talking about the Group A Streptococci (GAS) and theircapability to sometimes cause a flesh-eating disease callednecrotizing fasciitis, Derek decides to research this group a bitmore. As he reads, he quickly learns that
a. they are microaerophilic Gram-negative rods.
b. they are in the phylum ?-proteobacteria.
c. they are found Volume 4 of Bergeyâs Manual of SystematicBacteriology.
d. they have less than 50 mol % GC content.
e. none of the above

BIO 3124 Lecture Notes - Lecture 2: Tropism, Hiv, Papillomaviridae

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