ECO220Y1 Lecture Notes - Lecture 11: Probability Distribution, Standard Deviation, Graduate Management Admission Test

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13 Jun 2018
School
Department
Course
Professor
ECO220
Lecture 11
June 12, 2018
1
Chapter 9 (Cont.): Probability Distributions
Let Z ~ N(0, 1)
We covered:
(a) P(Z īµ’ 0.8) = ?
(b) P(0 īµ‘ Z īµ‘ k) = 0.3, k = ?
Theorem: Let X ~ N(ī‰Š, ī‰ī¬¶= variance)
Then īƑī¬æī®œ
ī®¢ ~ N(0, 1)
Example 1: Let X ~ N(50, ī‰ = 10)
(a) P(X īµ’ 60) = P( īƑī¬æī®œ
ī®¢ īµ’ ī¬ŗī¬“ī¬æī¬¹ī¬“
ī¬µī¬“ ) = P(Z īµ’ 1) = 0.1587
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ECO220Y1 Full Course Notes
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ECO220Y1 Full Course Notes
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Document Summary

Example 1: let x ~ n(50, = 10) (a) p(x (cid:3410) 60) = p( (cid:3410) (cid:2874)(cid:2868) (cid:2873)(cid:2868)(cid:2869)(cid:2868) ) = p(z (cid:3410) 1) = 0. 1587. Example 2: suppose gmat has an average score of 600 and standard deviation 100. June 12, 2018 (c) three students are writing the gmat. What is the probability that at least 2 of them have. = p(z > 1) = 0. 5 - 0. 3413 = 0. 1587 (cid:4667) We will approximate the numerical answer using the normal table. Normal approximation to binomial (d) suppose 500 students are writing the gmat. What is the probability that at least 300 of them have gmat scores over 700? p = p(x > 700) = 0. 1587. P(x (cid:3410) 300) = p(x = 300, 301, 302, 500) Let x ~ b(n = 500, p = 0. 4: the mean is at 200, the longest line will be at 200. In this example, find p(x > 300) = p(x = 301, 302, 500)

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