GGR270H1 Lecture Notes - Lecture 10: Klepton

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19 Jan 2018

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In the potassium iodide molecule, assume that the Kand I atoms bond ionically by the transfer of one electron from Kto I.

(a) The ionization energy of K is 4.34 eV, and theelectron affinity of I is 3.06 eV. What energy is needed totransfer an electron from K to I, to form K+ and Iâ ions fromneutral atoms? This is sometimes called the activation energy Ea.(b) Another model potential energy function forthe KI molecule is the Lennard-Jones potential:

where

r is the internuclear separation distance, and

and

are adjustable parameters. The Ea term is added to ensurecorrect asymptotic behavior at large r. At the equilibriumseparation distance r = ro = 0.305 nm, U(r) is a minimum, and U(ro)= â3.37 eV is the negative of the dissociation energy. Evaluate and

. (c) Calculate the force needed to breakup a KI molecule. (d) Calculate the force constantfor small oscillations about r = ro. Hint: Set r = ro +

, where /ro <<1 and expand

In an experiment done by scattering 5.5 Mev alpha particles on athin gold foil, students find that 10,000 particles are scatteredat an angle greater than 50 degrees. a) how many of these particleswill be scattered greater than 90 degrees? b) how many of theseparticles will be scattered between 70 and 80 degrees?

1. I know that N(theta)= 10,000
2. My book says the answers should be 2170 and 1347
3. My teacher told me that we do not need to use t,n,k, or e in theequation because they will cancel out.
4. I tried doing the problem the way my teacher told me to but Ican not seem to get the right answer.
5. Equation:N(theta)=([(Ni)(n)(t)]/16)((e^2)/(4pi*eo))[(z1*z2)^2/(r^2*k*sin(theta/2)^4))
6. becomes N(theta1)/N(theta2)=sin(theta2/2)^4/sin(theta1/2)^4
Please help :) greatly appreciated

GGR270H1 Lecture Notes - Lecture 10: Klepton

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