HMB265H1 Lecture : Notes taken during lecture
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HMB265H1 Full Course Notes
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Lecture sense of format and practise for the midterm the old midterms. aabb parent had two chromosomes: ab, ab. and in aabb, ab and ab are the two chromosomes. In f1 of linkage, it"s configuration will be ab chromosome and an ab chromosome. parents were double homozygous, recombination would not thus have any difference to the progeny without recombination. mostly f1 will make parental gametes, which are ab and ab: but with recombination in f1: ab and ab are the recombinant gametes. unlike how under mendelian ratios, the ratios are equal. can infer order of genes along chromosomes if look at many phenotypes and many crosses. If morgan is right, a+b+c = roughly a+c. ct and cv should have low proportion of recombinant phenotypes. Two inbred lines: test cross with vermilion eyes and cut wing edges, progeny produced. capitals for the pluses, lowercase for the non-