MAT135H1 Lecture Notes - Lecture 1: Inverse Function
8 Sep 2018
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Read sections 1. 1 -1. 5, appendix d from the textbook. An assignment that assigns a real number, and another real number, f ( ) Therefore, we input a real number as and the result is the output which is another real number as f ( ) The input is 2 because you are substituting as 2. The output is 5 when = 2 since 2(2) + 1 = 5 = f ( ) Given a function f , its inverse (if it exists) is a function f -1 such that whenever f ( ) = then f -1 ( ) = . The domain f -1 of is the codomain of f. The codomain f -1 of is the codomain of f. Therefore, inverses only exist for one-to-one functions where the domain of f is the input and the range of f -1 is the output.
