MAT136H1 Lecture Notes - Lecture 7: Antiderivative

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MAT136H1 Full Course Notes
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Mat136h1 s - lecture 7 - calculus 1(b) 1 x n+1 + c n 1 n + 1 ln x + c n = 1. Let u = 1 + ex du dx. = ex, dx = du ex ex u du ex. 2 + c = 2 1 + ex + c. Let u = 1 + ex e2 x. = ex, dx = du ex e2 x u du ex. Since u = 1 + ex, = ex u du = u 1 u du. Can do definite integrals by substitution - must remember to change bounds! = 2 1 + e1 2 1 + e0 = 2 1 + e 2 2. If hadn"t done the indefinite integral already in example 1, must use change bounds method: Let u = 1 + e x, dx = du e x. 1 u du in terms of x, the bound 0 and 1; but it is different for u.

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