Biology 1002B Lecture Notes - Fall 2018 Lecture 17 - Growth factor, Insulin-like growth factor 2, Transfer RNA
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Fill in the blank. Elongation during translation does NOT involve ____________.
Question 16 options:
the translation of codons according to the genetic code | |
the formation of bonds catalyzed by the ribosome | |
complementary base pairing between RNA molecules | |
amino acids being linked together in a polypeptide | |
reading the DNA template 3' to 5' |
For a given gene, what establishes the reading frame for translation?
Question 17 options:
the location of the enhancer relative to the gene | |
the first three nucleotides at the 5' end of the mRNA | |
the first three nucleotides at the 3' end of the mRNA | |
the start codon in the mRNA | |
the location of the promoter relative to the gene |
Which of the following is the LEAST likely direct consequence of a substitution mutation?
Question 18 options:
changing the length of a protein coded for by a gene | |
changing one amino acid in a protein | |
creating a stop codon | |
eliminating a start codon | |
changing the length of the DNA molecule containing a gene |
Suppose that the pre-mRNA transcript from a eukaryotic gene is 30,000 nucleotides long, and the gene codes for a sequence of 300 amino acids. What is the best explanation for the relationship between these numbers?
Question 19 options:
only the first 900 nucleotides of the pre-mRNA transcript are translated | |
it takes 100 nucleotides to specify a single amino acid | |
300 of the nucleotides in the transcript are important, and the rest are "junk" | |
only the last 900 nucleotides of the pre-mRNA transcript are translated | |
large portions of pre-mRNA transcripts are cut out during RNA processing |
Suppose an individual is born into a population with a novel mutation. Is the new mutation an evolutionary change, and why?
Question 20 options:
no, because it is not a big enough change to count | |
yes, because new mutations are always adaptive | |
yes, because the appearance of a new genetic variant is a genetic change in a population | |
no, because not enough individuals have the mutation for it to matter | |
no, because most mutations are not adaptive |
QUESTION 10
If you can drink milk as an adult, it means that you have inherited a mutation in the promoter of your lactase gene (the gene that encodes the enzyme you need to break down lactose). Predict the effect of this mutation:
The mutation changes the number of domains in the enzyme, which makes it work more efficiently | ||
The mutation changes the amino acid sequence of the lactase protein | ||
The mutation increases the number of copies of the lactase gene that will be found in your genome | ||
The mutation changes whether the lactase sequence is found in an intron or exon | ||
The mutation affects the expression of the lactase gene |
1.2 points
QUESTION 11
A competitive inhibitor is decreasing the activity of an enzyme. Predict the effect of adding more substrate to the reaction.
The substrate will increase the reaction rate by binding to the allosteric site | ||
The substrate will increase the reaction rate by competing with the inhibitor for the active site | ||
The reaction rate will not change unless the inhibitor can be removed | ||
The enzyme adjusts its shape so that the substrate, but NOT the competitive inhibitor, can bind | ||
The substrate will bind to the competitive inhibitor and block its ability to bind to the enzyme |
1.2 points
QUESTION 12
What determines where in the genome a transcription regulator will bind?
Transcription regulators bind to the 5' UTR region of a gene | ||
Regulators bind via complementary base-pairing to certain DNA molecules | ||
Covalent bonds form between the transcription regulator and the atoms of the DNA backbone | ||
Every eukaryotic gene has a different transcription regulator that will bind to the 5' end of the gene | ||
Transcription regulators bind to specific DNA sequences via multiple weak non-covalent interactions |
1.2 points
QUESTION 13
What is the basic premise of cell theory?
DNA -> RNA -> protein | ||
All cells arise from pre-existing cells | ||
DNA provides the complete instructions to create a cell | ||
The identity of a cell is determined through gene expression patterns | ||
All cells contain the same four basic macromolecules |
1.2 points
QUESTION 14
What is the benefit of using BOTH the lac activator and the lac repressor to control gene expression?
Using both an activator and repressor enables cells to more accurately determine the amount of lactose available in the environment | ||
Enzymes to digest lactose are only made when energy is low and lactose is available | ||
The activator can override the inhibition of the lac operon by the repressor | ||
The repressor can control the enhancer, while the activator can control the promoter | ||
When neither the lac activator or repressor is present, expression of the lac operon is too high |
1.2 points
QUESTION 15
What is the histone code used for?
Phosphorylation and acetylation of DNA affect its ability to be compacted | ||
Changes to the sequence of DNA change whether DNA will wrap around histone proteins | ||
Covalent modifications of histones affect the ability of the transcription initiation complex to form | ||
Histones provide the codon sequences needed for translation to occur | ||
The histone code affects which amino acids will get added to a polypeptide |