MATH 1300 Lecture Notes - Lecture 4: Product Rule, Global Positioning System, Power Rule

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Math 1300 lecture 4 notes the product rule. Introduction: example, example, find the points on the curve, where the tangent line is horizontal, solution, horizontal tangents occur where the derivative is zero. We have: thus d(cid:455)(cid:455)d(cid:454) (cid:1004) if (cid:454) (cid:1004) or (cid:454)(cid:1006) (cid:1006) (cid:1007) (cid:1004), that is, (cid:454) 6s(cid:1007) . So the gi(cid:448)e(cid:374) (cid:272)ur(cid:448)e has horizo(cid:374)tal ta(cid:374)ge(cid:374)ts (cid:449)he(cid:374) (cid:454) (cid:1004), s(cid:1007) , a(cid:374)d (cid:1006)s(cid:1007) . The (cid:272)orrespo(cid:374)di(cid:374)g points are s0, 4d, ss3 , 25d, and s2s3 , 25d: example, the equation of motion of a particle is, where s is measured in centimeters and t in seconds. Find the acceleration as a function of time. What is the acceleration after 2 seconds: solution, the velocity and acceleration are, the a(cid:272)(cid:272)eleratio(cid:374) after (cid:1006) s is as(cid:1006)d (cid:1005)(cid:1008) (cid:272)(cid:373)(cid:455)s(cid:1006), by analogy with the sum and difference rules, one might be tempted to guess, as. If f and t are both differentiable, then.

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