CHEM 1127Q Lecture Notes - Lecture 8: Unified Atomic Mass Unit

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Chem 1127q - lecture 6 - example problem for ch. 4. 319 g of dimethyl nitrosamine (containing c, h, n, and o) contains 1. 40 g carbon and 0. 355 g hydrogen. The compound contains 37. 82% by mass of nitrogen. Calculate how much carbon we have (in moles): 1. 40 g c / 12. 01 g/mol = 0. 1166 moles c. Calculate how much hydrogen we have (in moles): 0. 355 g h / 1. 008 g/mol = 0. 3526 moles h. Calculate how much nitrogen we have (in moles): 4. 319 g total x 0. 3782 n/total = 1. 633 g n. 1. 633 g n / 14. 01 g/mol = 0. 1166 moles n. Calculate how much oxygen we have (based on what"s left; in moles): 4. 319 g - 1. 40 g c - 0. 355 g h - 1. 633 g n = 0. 931 g o. 0. 931 g o / 16. 00 g/mol = 0. 0582 moles o.

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