a) Out of 100 observed individuals, you recorded the followinggenotypes:
30 D/D + 60 D/d + 10 d/d =100
Is this population in H-W Equilibrium? Use a = 0.05
b) In a sample of 1000 people, the observed phenotypes were 298blood group M (genotype MM), 489 group MN (genotype MN) and 213blood group N (genotype NN). Calculate the allele frequency of N(use 2 decimals).
30 D/D + 60 D/d + 10 d/d =100
Is this population in H-W Equilibrium? Use a = 0.05
b) In a sample of 1000 people, the observed phenotypes were 298blood group M (genotype MM), 489 group MN (genotype MN) and 213blood group N (genotype NN). Calculate the allele frequency of N(use 2 decimals).
Related textbook solutions
Related questions
| Blood Type | Genotype | # of individuals | Frequency of Genotype |
| M | MM | 360 | 0.36 |
| MN | MN | 480 | 0.48 |
| N | NN | 160 | 0.16 |
A population sample of 1,000 individuals was made for the MN blood group. The genotypes are easily measured since the alleles are co-dominant individuals were blood typed and the results are shown in the figure. Assume the population is in equilibrium. The frequency of M allele in the population is ? _______________. The frequency of the N allele in the population is ? ________________ Now suppose that the population is mating randomly : The frequency of the MM x MM mating is ?______________ The frequency of the MM x MN mating is ? _____________The frequency of MM x NN mating is ? _______________ The frequency of the MN x MN mating is?___________ The frequency of the MN x NN mating is ? ______________The frequency of the NN x NN mating is ?_____________
