1
answer
0
watching
701
views
10 Nov 2019

A solution containing possibly Ag+ , Hg2 2+ and/or Pb2+ ions was treated with 6 M HCl and a white precipitate resulted. The precipitate was treated with hot water and filtered. The filtrate from the hot water filtration was cooled and treated with HCl solution. At that time, a white precipitate resulted. A white residue on the filter paper was treated with NH3, and it disappeared. (2p) Group II Refer to the Flow Chart for Group II to answer following questions. Treatment of an unknown solution with H2S and pH 0.5 produced a black-brown precipitate. The precipitate was treated with KOH. After centrifugation, the supernatant KOH solution was acidified with 6M HCl and treated with H2S. No precipitate was found. The dark precipitate was treated with 6 M HCl and centrifuged. The supernatant HCl solution was treated with 6M NH3 and H2S. No precipitate formed. Treatment of the dark residue with 6 M HNO3 produced a yellow precipitate. The dark residue had dissolved. After centrifugation, the supernatant was blue. Treatment of the blue solution with 6M NH3 followed by centrifugation produced a deep blue solution and a white precipitate. (2p) Group III and IV Given the following facts, determine the metal present. A solution of the metals from groups III and IV was treated with NH3 and H2S. (1) The mixture was centrifuged; the solid was laid aside for future use. The supernatant liquid was treated with (NH4)2CO3. A white precipitate formed. The white precipitate was treated with 6M acetic acid. A clear solution resulted; the clear solution was treated with K2CrO4 and a yellow precipitate formed; the mixture above was centrifuge. The supernatant resulting was treated with (NH4)2C2O4; no precipitate resulted. The precipitate from (1) above was treated with 6 M HCl and dissolved completely; the solution obtained was treated with 6M NH3 and 3% H2O2. The mixture obtained was centrifuged. A yellow supernatant and a brown precipitate were obtained. The brown precipitate was dissolved in 6 M HCl and produced a deep red color when treated with KSCN. Write the formula of ions present in the original mixture

For unlimited access to Homework Help, a Homework+ subscription is required.

Casey Durgan
Casey DurganLv2
30 Mar 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in