A solution of 5.00 g of lauryl alcohol in 0.100 kg of benzene freezes at 4.1C. What is the approximate molar mass of lauryl alcohol? (The normal freezing point of benzene is 5.5C, and Kf for benzene is 5.12 C/m)

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Analyn TolentinoLv10

19 Nov 2020

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An organic acid was analyzed and the following percent composition was obtained: 68.85% Carbon, 4.9% hydrogen, 26.2 Oxygen. A solution of 1.02 g of this compound dissolves in 10.0 g of benzene freezes at 3.37 degrees C. The normal freezing point of benzene us 5.50 degrees C and it has a Kf of 5.12 C/m. Determine the molecular formula for this compound.

7.85 g of a compound with an unknown formula is dissolved in 300 g of benzene. The freezing point of the solution is 2.10 degrees celsius below that of pure benzene. What is the molar mass of the compound? (FP of pure benzene=5.51 degrees celsius; K_f(benzene)=5.12 degrees C/molal)

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1.25 grams of an unknown compound is dissolved into 85.0 grams of benzene, organic solvent with a freezing point depression constant, Kf = 5.12 C/m. The freezing point of pure benzene is 5.51 C and the freezing point of the solution is 4.50 C. Find the molar mass of the unknown compound.