Question

Aluminum hydroxide reacts with sulfuric acid as follows:
2 Al(OH)_{3 (s)} + 3 H₂SO_{4 (aq}) --> Al₂(SO₄)_{3 (s)} + 6 H₂O (l)

Questions:
A) Which reagent is the limiting reactant when 0.500 mol Al(OH)₃ and 0.500 mol H₂SO₄ are allowed to react?
B) How many moles of Al₂(SO₄)₃ can form under these conditions?
C) How many moles of the excess reactant remain after the completion of the reaction.