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12 Dec 2019
Aluminum hydroxide reacts with sulfuric acid as follows:
2Al(OH)3(s)+3H2SO4(aq)âAl2(SO4)3(aq)+6H2O(l)
1) Which reagent is the limiting reactant when 0.650 mol Al(OH)3 and 0.650 mol H2SO4 are allowed to react?
2) How many moles of Al2(SO4)3 can form under these conditions? Express the amount in moles to three significant digits.
3) How many moles of the excess reactant remain after the completion of the reaction? Express the amount in moles to three significant digits.
Aluminum hydroxide reacts with sulfuric acid as follows:
2Al(OH)3(s)+3H2SO4(aq)âAl2(SO4)3(aq)+6H2O(l)
1) Which reagent is the limiting reactant when 0.650 mol Al(OH)3 and 0.650 mol H2SO4 are allowed to react?
2) How many moles of Al2(SO4)3 can form under these conditions? Express the amount in moles to three significant digits.
3) How many moles of the excess reactant remain after the completion of the reaction? Express the amount in moles to three significant digits.
Reid WolffLv2
13 Dec 2019
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Al2(SO4)3(aq) + 6 H2O(l)
