The heat of vaporization of water is . How do you calculate the molar heat of vaporization of water?

Name: The heat of vaporization of water is . How do you calculate the molar heat of vaporization of water?
Uploaded: 2020-12-16T10:55:48+00:00
Description: The heat of vaporization of water is . How do you calculate the molar heat of vaporization of water?

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Carl David CepedaLv10

9 Oct 2020

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16 Dec 2020

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Related questions

During a strenuous workout, an athlete generates 2100.0 kJ of heat energy. What mass of water would have to evaporate from the athlete's skin to dissipate this much heat?
Note: At 100Â°C, the boiling point of water, the molar heat of vaporization of water is 40.67 kJ/mol. At 25Â°C, approximately room temperature, the molar heat of vaporization of water is 44.0kJ/mol.

The heat of vaporization of water at 100°C is 2.26 kJ/g; at 37°C (body temperature), it is 2.41 kJ/g.

a. Convert the latter value to standard molar heat of vaporization, ΔH°vap at 37°C.

b. Why is the heat of vaporization greater at 37°C than at 100°C?