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7.5=7.48+log([x]/[.04478-x]), how do i solve for x? This is forsubstituting in Henderson hasselbach. Please show sep by step
7.5=7.48+log([x]/[.04478-x]), how do i solve for x? This is forsubstituting in Henderson hasselbach. Please show sep by step
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watching
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Related questions
Using the Henderson-Hasselbach equation calculate the charge on these amino acids the various pH's in the table
Cys | His | Glu | Asp | Tyr | Arg | Lys | |
1.5 | |||||||
2.5 | |||||||
3.5 | |||||||
4.5 | |||||||
5.5 | |||||||
6.5 | |||||||
7.5 | |||||||
8.5 | |||||||
9.5 | |||||||
10.5 | |||||||
11.5 | |||||||
12.5 |
Please show the calculation if you can. And this is a biochemistry question