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The reaction for the combustion of propane is

C3H8(g)+5O2(g)â¶3CO2(g)+4H2O(l) ÎH=â526.3kcal/mol

How much heat is released when 38.9 g of propane is burned?

______ kcal

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Related questions

How much work is done at 1.2 atm and 284 K when 86 grams of oxygen reacts with excess propane in this combustion reaction.?

C₃H₈ (l) + 5O₂ (g) â 3CO₂ (g) + 4H₂O (l)

the combustion of propane (C3H8) produces CO2 and H2O.
C3H8 (g)+5O2(g)-> 3CO2(g) +4H2O(g)

the reaction of 5.39 mol of O2 with 12.9 mol of C3H8 will produce how many mol of H2O

Given the following information:

Species: C3H8(g), CO2(g), H20(l), O2(g)

Delta H^(degree)(subscript f) kJ/mol: -103.8, -393.5, -285.8, 0

Calculate delta H^(degree) for the combustion of one mole of propane C3H8, according to the equation:

C3H8 + 5O2 --> 3CO2 + 4H2O + heat

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