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13 Dec 2019

Given the following information:

Species: C3H8(g), CO2(g), H20(l), O2(g)

Delta H^(degree)(subscript f) kJ/mol: -103.8, -393.5, -285.8, 0

Calculate delta H^(degree) for the combustion of one mole of propane C3H8, according to the equation:

C3H8 + 5O2 --> 3CO2 + 4H2O + heat

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Keith Leannon
Keith LeannonLv2
17 Dec 2019

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Related questions

It's been a while since I took Chemistry 1.

1.Given the chemical reaction: 3 C(graphite) + 4 H2(g) --> C3H8(g)

Calculate the ∆Hrxn using Hess's Law and the following information:

C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l) ∆H = -2220 kJ/mol

C(graphite) + O2(g) --> CO2(g) ∆H = -393.5 kJ/mol

H2(g) + 1/2 O2(g) --> H2O(l) ∆H = -285.8 kJ/mol

2.Given the chemical reaction: C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l); ∆H = -2220 kJ/mol, calculate the heat given off when 0.48 g of C3H8 reacts with oxygen according to the reaction.

3.Given the chemical reaction: C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l); ∆H = -2220 kJ/mol, calculate the change in temperature of 150 g of water in a calorimeter when 0.48 g of C3H8 reacts with oxygen.

One mole of propane, C3H8 is placed in an adiabatic (isolated),constant pressure combustion chamber at 25C and allowed to reactwith a stoichiometric amount of oxygen and reacts to form H2O andCO2

1 C3H8 + 5 O2 -----> 4 H2O (g) + 3 CO2 (g)

Delta H C3H8 = -103.85 kJ/mole, Delta H CO2= -393.51 kJ/mole,Delta H H2O= -241.82 kJ/mole.

What is the enthalpy change for thereaction?

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