a. How will you decide whether the reactions in this experiment are spontaneous?

b. If you were to use this method after you had observed the fate of an ice cube at 25ËC, what would you conclude about the spontaneity of the following process? Why? H2O(s) â H2O(l)

c. The standard enthalpy change for this process is 6.01 kJ/mol. On the basis of your conclusions about the spontaneity, what is the minimum value for the standard entropy change?

answer

watching

112

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Jarrod RobelLv2

13 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

Consider the melting of ice for which âH_f = 6.01 kJ/mol at the normal freezing point (0Â°C). Find the standard entropy change for this process and then discuss the sign of your answer (meaning whether the value is positive or negative) with what you would expect qualitatively for this process.

answer should be 22.0 J/KÂ·mol

Here the sign should be positive since a liquid is formed from a solid. Liquids generally possess entropies higher than solids.

In the following reactionCH4+CH4 arrow CH3CH3+H2two C-H bonds are broken(bond energy =412 kj/mol) to form a new C-C bond(bond energy=348 kj/mol and a new H-H bond(bond energy=436 kj/mol). Estimate the enthalpy in this reaction. Is it endothermic or exothermic:Hint for exothermic reactions the combined energies of the new bonds should be larger than the combined energies of the broken bonds.Balanced the following unbalanced reaction and calculate its standard free energy change(under standard reactions). State whether the reaction is spontaneous or nonspontaneous under standard conditionsC2H5OH(l)+O2(g) arrow CO2(g)+H2O(l) C2H5OH(l) O2(g) CO2(g) H2O(l) deltaH kj/mol -277.7 0 -393.5 -285.8 deltaG kjmol -174.8 0 -394.4 -237.1

Weekly leaderboard

Home

Homework Help 3,900,000

Chemistry 830,000

Unlock all answers

Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

Principles of Chemistry Molecular Approach

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

Chemistry: The Central Science

Related questions

Weekly leaderboard