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13 Dec 2019

15) A gas of unknown molecular mass was allowed to effuse through a small opening under constantpressure conditions. It required 62 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 28 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas.

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Keith Leannon
Keith LeannonLv2
17 Dec 2019

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Related questions

A gas of unknown molar mass was allowed to effuse through a smallopening under constant pressure conditions. It required 184 s for1.00 L of this gas to effuse. Under identical experimentalconditions it required 506 s for 1.00 L of chlorotrifluoromethane(CClF3) gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter thetime required for effusion; that is, rate and time are inverselyproportional.)

Options:
a) The molar mass is 287.3 g/mol.
b) The molar mass is 790.0 g/mol.
c) The molar mass is 63.0 g/mol.
d) The molar mass is 173.2 g/mol.
e) The molar mass is 13.8 g/mol.

It took 4.2 minutes for 1.0 L of chlorine to effuse through a porous barrier. How long will it take for 1.0 L of O2 gas to effuse under identical conditions?

sulfur dioxide was allowed to effuse through a small opening under constant pressure conditions. It required 179 s for 1.00 L of this gas to effuse. Calculate the effusion time of arsine (AsH3) under identical experimental conditions. (Remember that the faster the rate of effusion, the shorter the time required for effusion; that is, rate and time are inversely proportional.)

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