Without doing any calculations determine what the sign of âS will be for the following equations. A. 2 CO(g) + O2(g) â 2 CO2(g) B. H2O(l) â H2O(g) C. C5H12(g) + 8 O2(g) â 5 CO2(g) + 6 H2O(g) Without doing calculations predict if the above reaction A is spontaneous given âHrxn = -566.0kJ

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13 Dec 2019

Without doing any calculations determine what the sign of âS will be for the following equations.

A. 2 CO(g) + O₂(g) â 2 CO₂(g)

B. H₂O(l) â H₂O(g)

C. C₅H₁₂(g) + 8 O₂(g) â 5 CO₂(g) + 6 H₂O(g)

Without doing calculations predict if the above reaction A is spontaneous given âH_rxn = -566.0kJ

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Sixta KovacekLv2

17 Dec 2019

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Related questions

) Without calculations, determine which of the following is ALWAYS spontaneous?

a) C2H6O (l) + 3 O2 (g) â 2 CO2 (g) + 3 H2O (g); ÎH < 0

b) The sublimation of dry ice (CO2 )

c) The freezing of water (H2O)

d) The formation of water from its gaseous elements

e) None of the above are ALWAYS spontaneous

1.Given the chemical reaction: 3 C_(graphite) + 4 H₂(g) --> C₃H₈(g)

Calculate the âHrxn using Hess's Law and the following information:

C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l) âH = -2220 kJ/mol

C_(graphite) + O₂(g) --> CO₂(g) âH = -393.5 kJ/mol

H₂(g) + 1/2 O₂(g) --> H₂O(l) âH = -285.8 kJ/mol

2.Given the chemical reaction: C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l); âH = -2220 kJ/mol, calculate the heat given off when 0.48 g of C₃H₈ reacts with oxygen according to the reaction.

3.Given the chemical reaction: C₃H₈(g) + 5 O₂(g) --> 3 CO₂(g) + 4 H₂O(l); âH = -2220 kJ/mol, calculate the change in temperature of 150 g of water in a calorimeter when 0.48 g of C₃H₈ reacts with oxygen.