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13 Dec 2019
Consider the titration of 50.0 mL of 0.0500 M (CH3)3N (a weak base; Kb = 6.40e-05) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added:
(a) 0.0 mL
pH =
(b) 6.3 mL
pH =
(c) 12.5 mL
pH =
(d) 18.8 mL
pH =
(e) 25.0 mL
pH =
(f) 35.0 mL
pH =
Consider the titration of 50.0 mL of 0.0500 M (CH3)3N (a weak base; Kb = 6.40e-05) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added:
| (a) 0.0 mL pH = | (b) 6.3 mL pH = | (c) 12.5 mL pH = |
| (d) 18.8 mL pH = | (e) 25.0 mL pH = | (f) 35.0 mL pH = |
Irving HeathcoteLv2
17 Dec 2019
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