Consider the titration of 50.0 mL of 0.0500 M H2NNH2 (a weak base; Kb = 1.30e-06) with 0.100 M HClO4. Calculate the pH after the following volumes of titrant have been added:(a) 0.0 mLpH = (b) 6.3 mLpH = (c) 12.5 mLpH = (d) 18.8 mLpH = (e) 25.0 mLpH = (f) 37.5 mLpH =

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