Log in
Chemistry
1
answer
0
watching
331
views

The solubility of lead(II) bromide, PbBr2, in water is 4.34 g/L. In an aqueous solution, an equilibrium exists between the dissolved ions and the solid salt.

 

1) Write the solubility product expression for this equation.

2) Calculate the molar concentration and the Ksp (solubility product constant) for lead(II) bromide.

 

Watch
1
answer
0
watching
331
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Patrick Suarez
Patrick SuarezLv10
24 Jan 2021

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Basic Chemistry
5 Edition,
Timberlake
ISBN: 9780134138046
Principles of Chemistry Molecular Approach
4th Edition,
Tro
ISBN: 9780134112831
Chemistry: Structure and Properties
2nd Edition,
Tro
ISBN: 9780134293936
Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Chemistry: A Molecular Approach
3rd Edition,
Tro
ISBN: 9780321809247
Chemistry: A Molecular Approach
5th Edition,
Tro
ISBN: 9780134874371
Principles of Chemistry: A Molecular Approach
4th Edition,
Tro
ISBN: 9780134895741
Chemistry: The Central Science
14th Edition, 2017
Brown
ISBN: 9780134414232

Related questions


Determine the molar amounts of Pb+2 and Cl-
use the values of this handout

If the Ksp of Ba(IO3)2 at 25°C is 6.0 X 10-10, what is the molar solubility of Ba(IO3)2?

In definition, solubility or molar solubility of a compound is the concentration of the dissolved solids in a saturated solution. Molar solubility can be solved using the given solubility product constant. 

For the compound C2D3, we can express this as the concentration of C and D in the aqueous solution. 

To solve for the molar solubility: 

Let S = molar solubility of C2D3 in mol L-1

[C] = 2S

[D] = 3S

 

Substituting this to the solubility product constant, Ksp formula, we'll have:

  

  

  

  

 

Thus, the molar solubility is 3.958 x 10 -5 M. 

8.Lead (II) iodide, Pb2, is an ionic compound with asolubility product constant Ksp of 7.9 x10-9. Calculate the solubility of this compoundin

  1. a. pure water.

b. 0.050 mol L-1 KI solution.

Weekly leaderboard

Home
Homework Help 3,900,000
Chemistry 830,000
Start filling in the gaps now
Log in