10 Nov 2021
Problem 29c
Page 280
Section 4.3: Derivatives and Shapes of Curves
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
10 Nov 2021
Given information
Given:-
Step-by-step explanation
Step 1.
To find the inflection points and concavity we have to find the second derivative of the given function.
now set the second derivative equal to zero and by solving the equation, we get the result below.
if we find the LCD of the denominator of those values we will get
whose LCM is 9. and has the factor of
so, the LCM for is the numeric part 9 and should be multiplied by the part of the variable.
so, we will multiply each term by and by simplifying we get the terms below.